z^2+2iz+2+4i=0

Solution for z^2+2iz+2+4i=0 equation:

Simplifying
z2 + 2iz + 2 + 4i = 0

Reorder the terms:
2 + 4i + 2iz + z2 = 0

Solving
2 + 4i + 2iz + z2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + 4i + 2iz + -2 + z2 = 0 + -2

Reorder the terms:
2 + -2 + 4i + 2iz + z2 = 0 + -2

Combine like terms: 2 + -2 = 0
0 + 4i + 2iz + z2 = 0 + -2
4i + 2iz + z2 = 0 + -2

Combine like terms: 0 + -2 = -2
4i + 2iz + z2 = -2

Add '-1z2' to each side of the equation.
4i + 2iz + z2 + -1z2 = -2 + -1z2

Combine like terms: z2 + -1z2 = 0
4i + 2iz + 0 = -2 + -1z2
4i + 2iz = -2 + -1z2

Reorder the terms:
2 + 4i + 2iz + z2 = -2 + -1z2 + 2 + z2

Reorder the terms:
2 + 4i + 2iz + z2 = -2 + 2 + -1z2 + z2

Combine like terms: -2 + 2 = 0
2 + 4i + 2iz + z2 = 0 + -1z2 + z2
2 + 4i + 2iz + z2 = -1z2 + z2

Combine like terms: -1z2 + z2 = 0
2 + 4i + 2iz + z2 = 0

The solution to this equation could not be determined.